510. Count all employees — challenge 2

DBMS Published 30 Sept 2026 Updated 30 Sept 2026 0 Views Verified

Write the MySQL 8.0 query. The goal is to solve the requirement correctly even when NULLs, duplicate rows or empty groups exist.

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Answer & Explanation

4 Answers

Verified

Option A

Use DELETE instead of SELECT.

Additional Explanation

This option is incorrect for the stated requirement.

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Option B

Use HAVING for a row-level predicate before aggregation.

Additional Explanation

This option is incorrect for the stated requirement.

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Option C

Use an unconditional CROSS JOIN.

Additional Explanation

This option is incorrect for the stated requirement.

Verified Correct Answer

Option D

SELECT COUNT(*) AS employee_count FROM employees;

Additional Explanation

Correct implementation. Prefer parameterized queries in application code, validate affected rows for UPDATE/DELETE, and use transactions for related writes.