2376. HR: Find managers with no direct reports. — Python + FastAPI + SQLAlchemy

DBMS Published 30 Sept 2026 Updated 30 Sept 2026 0 Views Verified

In a hr module, solve this as a production problem using Python + FastAPI + SQLAlchemy: Find managers with no direct reports. Provide the SQL, explain the logic, show safe application integration, and mention failure/edge cases.

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Answer & Explanation

4 Answers

Verified Correct Answer

Option A

SELECT e.id,e.name FROM employees e LEFT JOIN employees r ON r.manager_id=e.id WHERE r.id IS NULL AND EXISTS (SELECT 1 FROM employees x WHERE x.id=e.id AND x.status='active');

Additional Explanation

The self anti-join identifies managers without children; refine the manager definition according to the schema.

Verified

Option B

SELECT * FROM table_name;

Additional Explanation

Incorrect: it does not satisfy the stated business rule and can return/change unintended data.

Verified

Option C

DELETE FROM table_name;

Additional Explanation

Incorrect: it does not satisfy the stated business rule and can return/change unintended data.

Verified

Option D

UPDATE table_name SET status='active';

Additional Explanation

Incorrect: it does not satisfy the stated business rule and can return/change unintended data.